[Easy] Perfect Numbers

Given a number and check if a number is perfect or not. A number is said to be perfect if sum of all its factors excluding the number itself is equal to the number.

Input:
First line consists of T test cases. Then T test cases follow .Each test case consists of a number N.

Output:
Output in a single line 1 if a number is a perfect number else print 0.

Constraints:
1<=T<=300
1<=N<=10000

Example:
Input:
2
6
21
Output:
1
0

def perfect_numbers(n):
    sum = 0
    factors = list()
    for i in range(1,n+1):
        if n % i == 0:
            factors.append(i)
    factors = factors[:-1]
    for i in factors:
        sum += i
    if sum == n:
        return 1
    else:
        return 0

t = int(input())
for i in range(t):
    n = int(input())
    print(perfect_numbers(n))