Given a sorted array consisting 0’s and 1’s. The task is to find the index of first ‘1’ in the sorted array.
Input:
The first line of input contains an integer T denoting the number of test cases. Then T test cases follow. Each test case consists of two lines. First line of each test case contains an Integer N denoting size of array and the second line contains N space separated 0 and 1.
Output:
For each test case, in a new line print the index of first 1. If 1 is not present in the array then print “-1”.
Constraints:
1<=T<=300
1<=N<=105
0<=A[i]<=1
Example:
Input:
2
10
0 0 0 0 0 0 1 1 1 1
4
0 0 0 0
Output:
6
-1
def index_of_1(arr):
if 1 in arr:
return arr.index(1)
else:
return -1
t = int(input())
for i in range(t):
n = int(input())
arr = list(map(int, input().split()))
print(index_of_1(arr))
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